Fill in the table using this function rule

1 answer:

8 0

When x=3, y=9 and when x=6, y=3 bc u plug them into the equation

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alukav5142 [94]

$f(x) = \frac{x-3}{5}$
$g(x) = 5x+3$
$g(f(x)) = 5(\frac{x-3}{5})+3 = x-3+3 = x$

EDIT:
$f(g(x))=\frac{(5x+3)-3}{5}=\frac{5x+0}{5}=\frac{5x}{5}=x$

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