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Fofino [41]
3 years ago
15

Fill in the table using this function rule

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0
When x=3, y=9 and when x=6, y=3 bc u plug them into the equation
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Find the equation of the line that
olganol [36]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

Perpendicular lines have negative reciprocal gradients(slopes) so the slope of your new line would be 1/2. Then you use the point to find the new y-intercept

y=mx+b

2=\frac{1}{2}(8)+b

2=4+b

B=-2

y=\frac{1}{2}x-2

5 0
2 years ago
I don't know the answer or how to do it
Tju [1.3M]
In the first grid more squares are shaded than in the 2nd grid.
5 0
3 years ago
Read 2 more answers
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
Check picture if u kno geometry
Scorpion4ik [409]

Answer:

141.5 in

Step-by-step explanation

AB // CD // EF

12 / 15 = 21 / y        (By the property of 3 parallel lines and its transversals)

y = (15*21) / 12 = 26.25

CD // EF // GH

21 / y = x / 10       21 / 26.25 = x / 10

x = (21*10) / 26.25

x = 8

perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5

                               

4 0
2 years ago
Simplify please help
aleksandr82 [10.1K]

Answer:

4√10xy/32y is the answer. (I think)

5 0
2 years ago
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