Answer:
x <= 0 or 1 = < x <= 5.
Step-by-step explanation:
First we find the critical points:
x(x - 1)(x - 5) = 0
gives x = 0, x = 1 and x = 5.
Construct a Table of values:
<u> x < 0 </u> <u>x = 0 </u> 0<u>< x < 1</u> <u>1 =< x <= 5</u> <u>x = 5</u>
x <0 0 >0 <0 0
x - 1 <0 -1 >0 <0 0
x - 5 < 0 0 > 0 <0 0
x(x-1)(x-5) < 0 0 >0 <0 0
So the answers are x =< 0 or 1 =< x <= 5.
The object reaches the lowest height at 5 seconds
<h3>How to determine the time?</h3>
The function is given as:
f(t) = -2t² +22t + 6
Differentiate the function
f'(t) = -4t +22
Set to 0
-4t +22 = 0
Subtract 22 from both sides
-4t = -22
Divide both sides by -4
t = 5.5
Remove decimal points
t = 5
Hence, the object reaches the lowest height at 5 seconds
Read more about quadratic functions at:
brainly.com/question/1214333
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Answer:
2268 grams or 2 kg 268 g
Step-by-step explanation:
<u>How to convert Pounds to Grams</u>
1 pound (lb) is equal to 453.59237 grams (g).
1 lb = 453.59237 g
The mass m in grams (g) is equal to the mass m in pounds (lb) times 453.59237:
m(g) = m(lb) × 453.59237
In this case,
Convert 5 lb to grams:
2267.96 approximately convert to nearest thousands.
m(g) = 5 lb × 453.59237 = 2268 g or 2 kg 268 g
For this case we have the following equation:
![w = 0.9* \sqrt{E}](https://tex.z-dn.net/?f=w%20%3D%200.9%2A%20%5Csqrt%7BE%7D%20)
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
![w = 0.9* \sqrt{12}](https://tex.z-dn.net/?f=w%20%3D%200.9%2A%20%5Csqrt%7B12%7D%20)
Making the corresponding calculation:
Answer:
the approximate weight of the spring in pounds is: