Question

Maths assignment a^4-16

Answer 1

Answer:

$a^4-16$

$\left(a^2\right)^2-4^2$

$\left(a^2+4\right)\left(a^2-4\right)$

$=\left(a^2+4\right)\left(a+2\right)\left(a-2\right)$

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Answer 2

Step-by-step explanation:

The difference of squares: a² - b² factors to (a - b) (a + b)

Let x⁴ = (x²)²

Let 16 = 4²

Now by difference of squares x⁴ - 16 factors as (x² - 4)(x² + 4)

The front factor, (x² - 4), can factor by difference of squares again as (x - 2)(x + 2)