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Thepotemich [5.8K]
3 years ago
13

Please I need examples on using 111km in calculating the actual distance on ground when the map distance and scale is given

Geography
1 answer:
amm18123 years ago
3 0

Answer: Do it yourself

Find your scale. Maps have different scales e.g. for an explorers map 1:25,000.

Measure distance on map say in centimetres.

Use a ruler, string, or almost anything, pencil, fingers, a twig or I like a spare piece of paper.

Place against the scale for a direct reading.

Or calculate distance.

Say you measure 4 cm on the map. Then remember in this case 1:25,000.

so 4x1 or 4 = 4x25,000 = 100,000 cm real or actual distance.

In meters divide by 100 = 100,000/100 = 1,000 metres. (= 4cm on map).

or in kilometres divide again by 1,000 = 1,000/1,000 = 1 Kilometre. (= 4cm on map).

Also a tip just proved: 1:25,000 is the same as 4 cm = 1 Km or 1 cm = 1/4 Km real.

And best for walking a 1:50,000 scale map 2 cm = 1 Km or 1 cm = 1/2 Km real.

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Answer:

In explanation you see the answer but it I see it send it  different  so I just added a file so you can see clearly the way how this exercise works. Please, see the file attached

Explanation:

Let x = circumference of the circle

then

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and

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cancel pi into 39.48

A =  \left(\frac{\times^2}{12.566}\right)

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convert these fractions to decimal coefficients

A(x) = .0796x^2 + .0625x^2 - 6.625x + 175.5625

A(x) = .1421x^2 - 6.625x + 175.5625

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Find the axis of symmetry of this quadratic equation (min area)

x =   \frac{-\left(-6.625\right)}{2*.1421}

x =   \frac{6.625}{.2842}

x = 23.31 cm is the circumference when they have min area

Download docx
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