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Delvig [45]
3 years ago
11

What is an equation of the line that passes through the point (- 2, 7) and is perpendicular to the line x - 4y = 24 ? Pls help

Mathematics
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer: y=4x-1

Step-by-step explanation: the line goes through (-2,7) and is perpendicular to the line x-4y =24

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Nathaniel drives 45 miles in 30 minutes. If he drove three hours in total at the same rate, how far did he go?
yuradex [85]

Answer:

270 miles

Step-by-step explanation:

45x2=90

90x3=270

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K^2+5k-6=0 quadratic formula
s2008m [1.1K]
I hope this helps you



1.k^2+5k-6=0


a=1


b=5


c= -6


disctirminant =b^2-4ac


disctirminant =5^2-4.1. (-6)


disctirminant =49


x1= -(5)+ square root of 49/2.1



x1=-5+7/2


x1=1



x2= -5- square root of 49/2.1


x2= -5-7/2


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3 years ago
angles FGH and angles PQR are vertical angles. If angles FGH is 29, what is the measure of angles PQR?
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Answer:

< PQR = 61°

Step-by-step explanation:

Hope this helps:)

3 0
1 year ago
Blitzkrieg is the term used to describe Germany's?
Andreyy89
“lightning” warfare with tanks used to end a fight swiftly.
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3 years ago
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The map of a walking trail is drawn on a coordinate grid with three points of interest.
rewona [7]

Answer:

12 units

Step-by-step explanation:

Given the points :

R(−3, 2) - - - > S(2, 2) - - - - > T(2, −5).

Distance between R and S

Distance between two points is obtained thus :

D = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Distance between R and S

x1 = - 3 ; y1= 2 ; x2 = 2 ; y2 = 2

D1 = sqrt((2 - (-3))^2 + (2 - 2)^2)

D1 = sqrt((5^2 + 0^2))

D1 = sqrt(25)

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Distance between S and T

x1 = 2 ; y1= 2 ; x2 = 2 ; y2 = - 5

D2 = sqrt((2 - 2)^2 + (-5 - 2)^2)

D2 = sqrt((0^2 + (-7)^2))

D2 = sqrt(49)

D2 = 7

Hence, total length = D1 + D2 = 5 + 7 = 12 units

6 0
2 years ago
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