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Anna007 [38]
3 years ago
13

True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (

1 pts)
(5,2) is a solution to the equation 2x + 3y = 10.
Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

<u>answer (in words)</u>

FALSE. the coordinate pair (5, 2) is not a solution to the equation 2x+3y=10. in order to figure out whether or not the statement is true or false, plug the x and y values from the coordinate pair (5, 2) into the given equation, 2x+3y=10. if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>

<u>answer (algebraic/steps for solving)</u>

first, plug in 5 for x in the equation 2x+3y=10.

  • 2x+3y=10 ⇒ 2(5)+3y=10

then plug in 2 for y.

  • 2(5)+3y=10 ⇒ 2(5)+3(2)=10

now your equation is 2(5)+3(2)=10. all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

  • 2(5)+3(2)=10 ⇒ 10 + 3(2) = 10

multiply 3 · 2.

  • 10 + 3(2) = 10 ⇒ 10 + 6 = 10

add 10 + 6.

  • 10 + 6 = 10 ⇒ 16=10

16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation 2x+3y=10. in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

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3 years ago
Which functions are symmetric with respect to the origin?
Damm [24]

Answer:

The correct option is;

y = arcsinx and y = arctanx

Step-by-step explanation:

The given options are;

1) y = arcsinx and y = arccosx

Here, we have at the origin, where x = 0,  arccosx ≈ 1.57 while arcsinx = 0

Therefore arccosx does not intersect arcsinx at the origin for it to be symmetrical to arcsinx or the origin

2)  y = arccosxy and y = arctanx

Here arctanx = 0 when x = 0 and arcos x = 1.57 when x = 0 therefore, they are not symmetrical

3) y = arctanx and y = arccotx

Similarly, At x = 0, arccotx = 1.57 therefore, they are not symmetrical

4) y = arcsinx and y = arctanx

Both functions arcsinx and arctanx pass through the origin and their shapes are similar but inverted as they go from negative to positive.

3 0
3 years ago
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The
ExtremeBDS [4]

Answer:

  • 800 kph
  • 600 kph

Step-by-step explanation:

<u>Equation</u>

Let s represent the speed of the faster plane. Then its travel time is ...

  time = distance/speed = 3600/s

travel time for the slower plane is ...

  time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

  3600/(s -200) -3600/s = 1.5

<u>Solution</u>

Multiplying by (2/3)s(s -200), we get ...

  2400(s) -2400(s -200) = s(s -200)

  s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

  (s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

<u>Conclusion</u>

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

<em>Check</em>

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

6 0
3 years ago
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