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Stells [14]
3 years ago
11

I love you. You are worth it.

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer:

Thanks

Step-by-step explanation:

Zanzabum3 years ago
5 0

Answer:

WHAAA

Step-by-step explanation:

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12 T=______________lb
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5 0
4 years ago
Read 2 more answers
According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1
schepotkina [342]

Answer:

The probability that 121 or more Americans in the survey are afraid to fly is 0.1335.

Step-by-step explanation:

Let <em>X</em> denote the number of Americans afraid to fly.

The proportion of Americans afraid to fly is, <em>p</em> = 0.10/

A random sample of <em>n</em> = 1100 Americans are selected.

The random variable X follows a Binomial distribution with parameters n = 1100 and p = 0.10.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=1100\times 0.10=110>10\\\\n(1-p)=1100\times (1-0.10)=990>10

Thus, a Normal approximation to binomial can be applied.

So,  X\sim N(np,\ np(1-p))

Compute the probability that 121 or more Americans in the survey are afraid to fly as follows:

P(X\geq 121)=P(\frac{X-np}{\sqrt{np(1-p)}}>\frac{121-110}{\sqrt{99}})\\\\=P(Z>1.11)\\\\=1-P(Z

Thus, the probability that 121 or more Americans in the survey are afraid to fly is 0.1335.

4 0
3 years ago
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