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3 years ago

If m < C is greater than m < E, then AB is _________ DF.

Mathematics

1 answer:

Bess [88]3 years ago

6 0

Answer:

B longer than

Step-by-step explanation:

In the attached figure it is mentioned that

BC $\cong$ DE

And AC $\cong$ FE

Now the relationship between the slides i.e.

AB and DF if ∠C > ∠E

Now as we can see that the corresponding sides are congruent with each other

So ∠C > ∠E,

Therefore opposite sides of the mentioned triangles would be in the similar ratio as the angles are in

Therefore the option B is correct

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4× 4 3/10= 4×43/10= 86/5= 17 1/5

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4 years ago

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Answer:

44 is not an perfect square

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PLEASE HELP WILL GIVE BRAINLIEST! What is the following sum? Assume x > or equal to 0 and y is > or equal to 0.

Ira Lisetskai [31]

Answer:

Option (b) is correct.

The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

Step-by-step explanation:

Given:Expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ .

$\sqrt{x^2y^3}$ can be written as $\sqrt{x^2y^2y}=xy\sqrt{y}$

Also, $2\sqrt{x^3y^4}$ can be written as $2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}$

Now, the given expression becomes,

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

$=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$ .

Now, adding like term, terms having same variable with same degree.

$=2xy\sqrt{y}+2xy^2\sqrt{x}$ .

Thus, The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

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3 years ago

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Tems11 [23]

hi <3

lets call the unknown number 'x' for now and form an equation from what we know

1/3(x-9) = 15

now multiply both sides by 3

x - 9 = 45

add 9 to both sides

x = 54

hope this helps :)

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Phantasy [73]

Answer:

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Step-by-step explanation:

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