1/2, 3/8, 1/7 hopefully I am right I’m not sure
Good Job
And always keep your eyes on ur own paper
Hi there!
![\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bf%5E%7B-1%7D%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D%20%7D)

Find the inverse by replacing f(x) with y and swapping the x and y variables:

Isolate y by adding 4 to both sides:

Divide both sides by 9:

Take the cube root of both sides:
![y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D%5C%5C%5C%5Cf%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%2B4%7D%7B9%7D%20%7D)
£4 and 720p, 12 times 60p equals 720p
Answer:

Step-by-step explanation:
![Volume\:of\:cube:V=a^{3} \:(a\:is\:the\:length\:of\:each\:edge)\\\Leftrightarrow a=\sqrt[3]{V} \Leftrightarrow a=\sqrt[3]{729} =9](https://tex.z-dn.net/?f=Volume%5C%3Aof%5C%3Acube%3AV%3Da%5E%7B3%7D%20%5C%3A%28a%5C%3Ais%5C%3Athe%5C%3Alength%5C%3Aof%5C%3Aeach%5C%3Aedge%29%5C%5C%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7BV%7D%20%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7B729%7D%20%3D9)