Answer:
8% probability that he or she actually has the disease
Step-by-step explanation:
We use the Bayes Theorem to solve this question.
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?
This means that:
Event A: Test comes back positive.
Event B: Having the disease.
Test coming back positive:
2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that 
For the 100-2 = 98% who do not have the disease, the test comes back positive 100-77 = 23% of the time.
Then

Finally:

8% probability that he or she actually has the disease
Answer:
54
Step-by-step explanation:
Multiply:
<em>37x37=72</em>
<em>Subtract:</em>
<em>180-72=108</em>
<em>Divide:</em>
<em>108/2=54</em>
Answer:
yes, sounds linear.
this is an mx + b scenario.
here's the model:
y = )3/1)x + 50
or
y = 3x + 50
where the 1 in the slope denominator is a square foot.

Part A
To find the ticket price when the price is $16
Let us substitute the value of t = 16
p = -10 x (16 x16) + 500 x 16 + 60
p = -2560 + 8000 + 60
p =$ 5500
Part B
To get the maximum profit, we will have to differentiate P with respect to t

The maximum profit will be obtained when the derivative is zero
-20t + 500 = 0
20t = 500
t = 500/20
t = 25
This means that the ticket price has to be $25 so as to obtain the maximum price
Part C
The maximum profit will be obtained by substituting t = 25 into the original equation