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3 years ago

How do I find the next four of the sequence?

Mathematics

2 answers:

maxonik [38]3 years ago

8 0

Step-by-step explanation:

In this arithmetic sequence, the common difference d is 7. You can find this by subtracting a term from the consecutive term: 16 - 9 = 7, 23 - 16 = 7. In order to find the next four terms, keep adding 7 to the previous term. The next four terms are 30, 37, 44, and 51.

lawyer [7]3 years ago

8 0

Answer:

Step-by-step explanation:

$a_{1}$ = $\frac{3}{4}$

d = - $\frac{1}{4}$

$a_{2}$ = $\frac{3}{4}$ + ( - $\frac{1}{4}$ ) = $\frac{1}{2}$

$a_{3}$ = $\frac{1}{2}$ - $\frac{1}{4}$ = - $\frac{1}{2}$

$a_{4}$ = - $\frac{1}{2}$ - $\frac{1}{4}$ = - $\frac{3}{4}$

$a_{5}$ = - $\frac{3}{4}$ - $\frac{1}{4}$ = - 1

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K is the set of consonant letters in the English alphabet h ∈ K Is this true or false?

Stells [14]

∈ <--- This symbol means "an element of". According to your question, you would like to know if statement h ∈ K is valid. That statement is true because the letter "h" is a consonant and set K is a set of consonants. If we look at set K, it should look like this:

K = {B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Y, Z}. As seen in this set, the letter "h" is the 6th element.

Therefore, h ∈ K is a valid statement. The answer is: TRUE.

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3 years ago

Evan has a loyalty card good for a discount at his local hardware store. The item he

Eva8 [605]

Answer:

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3 years ago

Need help due tmr :)

aliina [53]

A.) height(h), diameter Sphere(d) = 14.6 in., diameter Cylinder (l) = 11 in.

d^2 = h^2 + l^2
h^2 = d^2 - l^2
h^2 = 14.6^2 - 11^2
h^2 = 213.16 - 121
h^2 = 92.16
h = 9.6 in.

b.) V = (4/3)(pi)(r^3)
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3 years ago

How do you do question number 5? If you do it can you please explain how to do it? Thank you!!

erik [133]

F(-3) = 4(-3) - 3 = -12 - 3 = -15.
H(2) = -5(2) + 7 = -10 + 7 = -3.

F(-3) + H(2) = -15 + -3 = -18.

The solution is -18.

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4 years ago

Read 2 more answers

Find the radius of convergence of the power series. (if you need to use or –, enter infinity or –infinity, respectively. ) [infi

Alona [7]

For given power series $\sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}$ the radius of convergence is 2.

For given question,

We have been given a power series $\sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}$

We need to find the radius of convergence of the power series.

We use ratio test to find the radius of convergence of the power series.

Let $a_n=\frac{(-1)^nx^n}{2^n}$

$\Rightarrow a_{n+1}=\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}$

Consider,

$\lim_{n \to \infty}|\frac{a_{n+1}}{a_n} |\\\\= \lim_{n \to \infty} |\frac{\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}}{ \frac{(-1)^nx^n}{2^n} } |\\\\=\lim_{n \to \infty} |\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}\times \frac{2^n}{(-1)^nx^n} |\\\\=\lim_{n \to \infty} |\frac{(-1)x}{2} |\\\\=\lim_{n \to \infty}|\frac{-x}{2} |\\\\=\frac{x}{2}$

By Ratio test, given power series converges at $|\frac{x}{2} | < 1$

⇒ |x| < 2

So, the radius of convergence is 2.

Therefore, for given power series $\sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}$ the radius of convergence is 2.

Learn more about the radius of convergence here:

brainly.com/question/2289050

#SPJ4

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2 years ago