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3 years ago

Given z1 = 2 + sqrt 3i and z2 = 1 – sqrt 3i, what is the sum of z1 and z2?

Mathematics

1 answer:

icang [17]3 years ago

7 0

Answer:

its B. 3

^-^

Step-by-step explanation:

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Find the collame of boid of dimension 16cm X 10m x 6cm.

swat32

Question: Find the volume of cuboid of dimension 16cm X 10cm x 6cm.

Answer: Given Length=16cm, Breadth=10cm, Height=6cm

Using Volume formula for cuboid:-

$volume = l \times b \times h$

$→16 \times 10 \times 6$

$→960 \: cm^{3}$

So, volume of cuboid is 960 cm³

7 0

3 years ago

Trisha packs x boxes with 12 bottles in each box. The total number of bottles she packs is 216. Which equation and solution repr

LiRa [457]

Answer:

Number of boxes Trisha pack = 18 boxes

Step-by-step explanation:

Given:

Number of boxes Trisha pack = X

Number of bottles in each box = 12

Total number of bottle = 216

Find:

Number of boxes Trisha pack

Computation:

Total number of bottle = Number of boxes Trisha pack x Number of bottles in each box

216 = X × 12

X = 216 / 12

X = 18

Number of boxes Trisha pack = 18 boxes

4 0

3 years ago

Read 2 more answers

What is -13/6(12/7)=

-BARSIC- [3]

Answer:

-267

Step-by-step explanation:

−136(127)

=(−136)(127)

=(−13)(12)(6)(7)

=−15642

= −267

5 0

3 years ago

Read 2 more answers

Answer this maths watch question step-by-step

Scilla [17]

The value of a is 2 and the value of b is 6.

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization. One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

You should factor the given expression.

$2-\frac{x+3}{x+1}-\frac{x-5}{x-1}\\ \\ 2+\frac{-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \mathrm{Apply\:the\:fraction\:rule}:\quad \:a+\frac{b}{c}=\frac{ac+b}{c}\\ \\ \frac{2\left(x+1\right)\left(x-1\right)-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \frac{2x+6}{\left(x+1\right)\left(x-1\right)}=\frac{2x+6}{x^2-1}$