Ask question

Ask question

All categories

3 years ago

15

(x+5)²=81 need help quick

1 answer:

Vilka [71]3 years ago

5 0

Square root each side
x-5=positive/negative 9
x=14, and -4

You might be interested in

If f(x) = x2 – 6x + 14, what is f(-2)?

Paraphin [41]

Answer: −28

i think ?????

4 0

2 years ago

Read 2 more answers

Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.

fgiga [73]

Answer:

QN = 3√7
OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

DQ = (3 units)·3 = 9 units

KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

KI² = KO² +OI²

4² = 3² +OI²

OI = √(16 -9)

OI = √7

QN = 3·OI = 3√7

8 0

3 years ago

The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th

choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

$f_x(x) = \dfrac{1}{1500} ; o \le x \le \ 1500$

The function of the insurance is:

$I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \ \ \ \ 250 \le x \le 1500}} \right.$

Hence, the variance of the insurance can also be an account forum.

$Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2$

here;

$E[I(x)] = \int f_x(x) I (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}$

$\dfrac{5}{12} \times 1250$

Similarly;

$E[I^2(x)] = \int f_x(x) I^2 (x) \ sx$

$E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx$

$= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}$

$\dfrac{5}{18} \times 1250^2$

∴

$Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]$

Finally, the standard deviation of the insurance payment is:

$= \sqrt{Var(I(x))}$

$= 1250 \sqrt{\dfrac{5}{48}}$

≅ 404

4 0

2 years ago

A rectangular prism has a length of 212 centimeters, a width of 212 centimeters, and a height of 5 centimeters. Justin has a sto

BlackZzzverrR [31]

Answer:

$3.75\ cm^{3}$ or $3\frac{3}{4}\ cm^{3}$

Step-by-step explanation:

step 1

Find the volume of the rectangular prism

we know that

The volume of a rectangular prism is

$V=LWH$

In this problem we have

$L=2\frac{1}{2}\ cm=\frac{2*2+1}{2}=\frac{5}{2}\ cm$

$W=2\frac{1}{2}\ cm=\frac{2*2+1}{2}=\frac{5}{2}\ cm$

$H=5\ cm$

substitute in the formula

$V=(\frac{5}{2})(\frac{5}{2})(5)=\frac{125}{4}=31.25\ cm^{3}$

step 2

Find the difference between the volume of the prism and the volume of the storage container

$35\ cm^{3}-31.25\ cm^{3}=3.75\ cm^{3}$

$3.75=3\frac{3}{4}\ cm^{3}$

3 0

3 years ago

The product of a number and the difference of the number and 5

tatiyna

X(x-5)
this is because product is multiplcation and difference is subtraction. The multiplication of a subtraction problem is distribution

6 0

3 years ago