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Ray Of Light [21]
3 years ago
14

Complete the first step in the solution. x/3 = 11

Mathematics
2 answers:
Korolek [52]3 years ago
3 0
Multiply by three to cancel the denominator.
lapo4ka [179]3 years ago
3 0
X/3 / 3 = 11 / 3 I hope this helps
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Please help me with this please and thank you
Ierofanga [76]

Step-by-step explanation:

a geometric sequence means that every term is created by multiplying the previous term by a certain constant factor. this factor is called the "common ratio".

so,

6×r = 18

r = 18/6 = 3

and a quick check tells us this works also for the next terms (18×3 = 54, 54×3 = 162), so it is indeed a geometric sequence with common ratio 3.

a0 = 6

a1 = a0 × 3 = 6×3 = 18

a2 = a1 × 3 = a0 × 3×3 = 6×3² = 54

an = a0 × 3^n = 6 × 3^n

so,

f(x) = 6×3^x, x is integer, x >=0

4 0
2 years ago
3(x - 5) = 30<br> I dont know how to solve this
Anastaziya [24]

Answer:

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Step-by-step explanation:

3(x-5)=30

First, you would distribute the three to the x and the negative five.

3x-15=30

Then you would add 15 to the 15 to cancel it and to the 30 to make it even.

3x-15=30

  +15=+15=

3x=45

Finally, you would divide 3 into both sides, cancelling out the three and fiving you,

x=15

Hope this helped!

3 0
3 years ago
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Ksenya-84 [330]

Answer:

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Step-by-step explanation:

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larisa86 [58]

Answer:

C ( I think so)

Step-by-step explanation:

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