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3 years ago

(-8)+(-19) i will give brainllest

Mathematics

2 answers:

ANEK [815]3 years ago

8 0

Answer:

-27 maybeeeeeeeeeeeee

MrRissso [65]3 years ago

4 0

Answer:

-27

Step-by-step explanation:

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If Richard worked for 7 dollars and made 9 dollars and hour how much would he make?

Artemon [7]

Answer:

$63

Step-by-step explanation:

I believe you meant Richard worked for 7 hours and made $9 per hour.

In order to know how much Richard earned for 7 hours, you have to multiply Richard's salary rate with his number of working hours.

7 hours x 9 dollars/hour = $63

Therefore, Richard earned $63 for his 7-hour work.

Additional Information

Another example is: if Richard worked for 10 hours, you just have to multiply his salary rate again to his number of working hours.

10 hours x 9 dollars/hour = $90

5 0

3 years ago

Madison and her sister went to the store together. After the store, Madison walked 2 blocks west to get a coffee and her sister

ladessa [460]

Answer: 5 blocks

Step-by-step explanation:

If they both walked in the same direction, they both will be the same distance from each other.

If Madison went to a coffee shop 2 blocks west from the store, and her sister went from the store they were previously at to her job 7 blocks west, then, since they walked in the same direction, they would only be 5 blocks away.

Hope this helps :)

-jp524

5 0

3 years ago

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David earns a base rate of $12 an hour and receives a weekly attendance award of $20. he works 40 hours this week. what would be

Pavel [41]

20+12x
20+12(40)
20+480
500
total compensation for this week = $500

7 0

3 years ago

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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e

My name is Ann [436]

Answer:

$\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)} \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

Step-by-step explanation:

If the system contains $n$ atoms, we can arrange $r$ quanta of energy in

$\binom{n}{r} = \dfrac{n!}{r!(n-r)!}$

ways.

$\mathbf{a)}$

In this case,

$n = 2, r=1$ .

Therefore,

$\binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2$

which means that we can arrange 1 quanta of energy in 2 ways.

$\mathbf{b)}$

In this case,

$n = 20, r=10$ .

Therefore,

$\binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756$

which means that we can arrange 10 quanta of energy in 184 756 ways.

$\mathbf{c)}$

In this case,

$n = 2 \times 10^{23}, r = 10^{23}$ .

Therefore, we obtain that the number of ways is

$\binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

3 0

3 years ago

2 + 2 = ? idk the answer bro i need help

Leto [7]

Answer:

That would be 4 man

8 0

3 years ago

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