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Katen [24]
3 years ago
14

Pls pls help

Mathematics
2 answers:
Savatey [412]3 years ago
7 0

Answer:

One

Step-by-step explanation:

This equation is not a quadratic and can be solved to get an integer solution

romanna [79]3 years ago
7 0

Answer:

Step-by-step explanation:

It can have at most 1 sensible answer. It may have zero and infinitely many

3x + 6 = - 1 - 3 + 4x              Combine the right

3x + 6 = - 4 + 4x                   Add 4 to both sides

3x + 6 + 4 = 4x                     Subtract 3x from both sides

3x  + 10 -3x = 4x - 3x             Combine

10 = x

The only answer (1) that is possible is 10.

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3 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}

y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0

Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

so that with r = 4/5, the coefficients are governed by

c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}

c) Starting with c_0=1, we find

c_1 = -\dfrac{c_0}5 = -\dfrac15

c_2 = -\dfrac{c_1}{10} = \dfrac1{50}

so that the first three terms of the solution are

\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

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2 years ago
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kotegsom [21]
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3 years ago
In a factory, a manager tests 250 products and finds defects in 7 of them. How many defects are likely going to be in a 10,000 u
Natalka [10]

Answer:

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Step-by-step explanation:

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