All categories

3 years ago

Solve. 2(7y - 5) = 4

Mathematics

2 answers:

Brrunno [24]3 years ago

8 0

Answer:

y=1

Step-by-step explanation

So basically 2 *7y is 14y and 2*5 equals 10

bring the 10 to the 4 and you have 14y=14

y=1

Inessa [10]3 years ago

3 0

14y-10=4
+10 +10
14y= 14
Y=1

You might be interested in

I need help. I'm confused

Alex

So, it is most likely that Joel runs 7 miles a day. On the x-axis would be the number of days he runs and the y-axis would be the mileage.

4 0

3 years ago

Please show me step by step on how to solve this.

Readme [11.4K]

Well, you have to be given an interval. That is not an interval.

You should be given something like $1 \leq x \leq 2$

If you add those fractions up you'll just get a point on the number line.

Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3

You'll end up with a point on 2/3

7 0

3 years ago

What is the value of the rational expression<br> 2x- 1<br> x+5<br> when x = 0?

nikitadnepr [17]

Answer:

Step-by-step explanation

becasue 2x0=0 and 1x0=0

and when you add 5 to 0 you get five

7 0

2 years ago

PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

3 years ago

Please help me solve!

Elina [12.6K]

Answer:

Step-by-step explanation:

Comment

There are a number of ways of doing this problem. I don't know which method you are intended to use. One sure way in this case is graphing the equation, I have done this for you. See below. The maximum volume occurs where x = 2

The graph shows that there is a peak at x = 2. That is where the maximum volume is,

Answer

x = 2

6 0

2 years ago