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mezya [45]
3 years ago
13

Find all angles, 0° sin a= 0

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0

Answer:

theta = 0   theta = 180

Step-by-step explanation:

sin theta = 0

sin ^-1 (sin theta) =sin^-1( 0)

theta = 0   theta = 180  for the limits of theta between 0 and 360

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calvin paints pictures and sells them at art shows.he charges $56.25 for a large paiting.he charges $25.80 for a small pating.la
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Calvin made a total of $414.90
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
Which is closer 0.7 miles or 0.25 miles
Vadim26 [7]
0.25 miles is closer
5 0
4 years ago
Read 2 more answers
Khaleej Times)Petrol prices in the UAE have jumped over 56 per cent since January 2022 due to an increase in global crude oil pr
Paraphin [41]

Answer:

it will equal1to indequate it

8 0
2 years ago
What is the rate of change of the perimeter of the square at the instant the area is 49 m2?
vagabundo [1.1K]
Let x = the length of a side of the square (m).
The area is
A = x²
The perimeter is
P =  4x

The rate of change of P with respect to x is
P'(x) = 4  (independent of x)

When A = 49 m², then x = 7 m.
The rate of P is 4.

Answer: 4
6 0
4 years ago
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