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2 years ago

I WILL MAKE YOUR ANSWER THE BRAINLIST MAKE SURE YOU ARE RIGHT FIND THE VOLUME OF THE CONE

Mathematics

1 answer:

Natasha2012 [34]2 years ago

8 0

Answer:

301.59

Step-by-step explanation:

V=1/3hπr²

sorry in advance if its wrong, this is my 1st time answering this type of question. that's what i got for the answer

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Solve for c in the scientific formula C=Wtc/1000

Troyanec [42]

C = Wtc/1000

1000C = Wtc

Wtc = 1000C

W = (1000C) / (tc)

This is assuming that C and c are not the same.

If they are the same, we have:

W = (1000) / t, provided ,that C and c are not equal to 0.

3 0

2 years ago

A b c or d? help me

kotegsom [21]

Answer:

B.) $\frac{1}{2} +8$

Step-by-step explanation:

$\frac{1}{2}-(-8)$

A negative and a negative equals a positive. Remove parentheses and simplify

$\frac{1}{2}+8$

Done.

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2 years ago

Read 2 more answers

How many different 2-person conversations would happen at a party of 30 people

tigry1 [53]

15 because simple division 30 divided by 2 is 15 only 15 can happen

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2 years ago

find the digit in units place in the expansion of the following: 1) 2¹⁹⁶⁷ 2) 3¹⁹⁶⁹ 3)4¹⁹⁷⁰ 4) 4¹⁹⁷¹ 5) 5⁵⁵⁵ 6) 6¹⁰⁰⁰ 7) 7²⁰⁰⁷ 8)

diamong [38]

Answer:

troll

Step-by-step explanation:

troll!!!!!!!!!!!!!!!!!!!!!!

5 0

2 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago