The value of y would be 20 times more valuable than 12 because the pattern for this table is y=20x. Let me know if I'm right :)
Answer:
106.1 ft/s
Step-by-step explanation:
You know the diagonal of a square is √2 times the length of one side, so the distance from 3rd to 1st is 90√2 feet ≈ 127.2792 ft.
The speed is the ratio of distance to time:
speed = distance/time = 127.2972 ft/(1.2 s) ≈ 106.1 ft/s.
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In case you have never figured or seen the computation of the diagonal of a square (the hypotenuse of an isosceles right triangle), consider the square with side lengths 1. The diagonal will cut the square into halves that are isosceles right triangles with leg lengths 1. Then the Pythagorean theorem can be used to find the diagonal length d:
d² = 1² + 1²
d² = 2
d = √2
Since this is the diagonal for a side length of 1, any other side length will serve as a scale factor for this value. A square with a side length of 90 ft will have a diagonal measuring 90√2 ft.
Answer:
y=7x+3
Step-by-step explanation:
Hi there!
We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)
First, let's find the slope of y=7x-5, since parallel lines have the same slopes
The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since 7 is in the place of where m is, the slope of the line is 7
It's also the slope of the line parallel to it.
We can substitute 7 as m into the formula y=mx+b for our new line:
y=7x+b
Now we need to find b
Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x
31=7(4)+b
Multiply
31=28+b
Subtract 28 from both sides
3=b
Substitute 3 as b
y=7x+3
Hope this helps!
Answer:
(-1,-7)
Step-by-step explanation:
Substitute 2x-5 (from the first equation) as the y-value for the second equation, so you have something that looks like this:
2x-5 = -2x-9
Add 2x to both sides: 4x-5 = -9
Add 5 to both sides 4x = -4
Divide both sides by 4: x = -1
Substitute -1 for x in either equation (you'll get the same y-value)