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Hitman42 [59]
3 years ago
11

Evan borrowed money from his mom. If he paid her back 9.60 which is 20% of the total he owns, then how much did he owe her to be

gin with
Mathematics
1 answer:
lyudmila [28]3 years ago
7 0

Given:

Evan paid his mom back 9.60 which is 20% of the total he owns.

To find:

How much did he owe her to begin with.

Solution:

Let x be the amount Evan owns.

According to the question,

20% of x = 9.60

\dfrac{20}{100}x=9.60

\dfrac{1}{5}x=9.60

Multiply both sides by 5.

x=48

Therefore, Evan owns 48 from his mom.

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Step-by-step explanation:

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3 years ago
Solve using square roots 3x^2+25=73
seropon [69]
Heya !

Given expression -

3 {x}^{2} + 25 = 73

Subtracting 25 both sides ,

3 {x}^{2} + 25 - 25 = 73 - 25 \\ \\ 3 {x}^{2} = 48

Dividing by 3 on both sides ,

\frac{3 {x}^{2} }{3} = \frac{48}{3} \\ \\ {x}^{2} = 16

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x = + \: 4 \: \: \: \: or \: \: - 4 \: \: \: \: \: \: \: Ans.
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4 years ago
I’d really appreciate if you’d also give a brief explanation:)
ArbitrLikvidat [17]

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Only area of PQR can be calculated.

Step-by-step explanation:

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3 0
3 years ago
Please Help !!!
solong [7]
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)

moles LiCl required = 4.37
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Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
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moles Cu in excess = 4.2 - 3.15 =1.05

N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
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4 years ago
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