1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tresset [83]
3 years ago
13

Which of the following is a biconditional statement?

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

i think it might be D i could be wrong

You might be interested in
20 subtracted from the product of x and 10
Ksju [112]

Answer:

10x-20

Step-by-step explanation:

x times 10 is 10x

10x - 20 = 10x - 20

in conclusion you cannot subtract a number from a variable

3 0
3 years ago
Read 2 more answers
Mean, Mode, Med<br> 86, 12, 11, 12, 15, 29, 59, -40
Liono4ka [1.6K]

Answer:

Step-by-step explanation: so first u wanna put them in order -40, 11, 12, 12, 15, 29, 59, 86

The median is pretty much the number in the middle so it’s 15. Mode is the number that repeats the most so it’s 12. And mean is adding all the numbers together and then dividing it by how many numbers are there. So it is 23

6 0
3 years ago
In what number base is the addition 456+24+225=1050​
jasenka [17]

This additition is false

the true answer is 705

Its base on my understanding:)

<h3>꧁✰_______❀Edilyn❀_______✰꧂</h3><h3 />

<em>#</em><em>C</em><em>a</em><em>r</em><em>r</em><em>y</em><em>O</em><em>n</em><em>L</em><em>e</em><em>a</em><em>r</em><em>n</em><em>i</em><em>n</em><em>g</em>

<em>#</em><em>N</em><em>o</em><em>T</em><em>o</em><em>C</em><em>o</em><em>p</em><em>y</em><em>P</em><em>a</em><em>s</em><em>t</em><em>e</em>

<h3 /><h3><em>F</em><em>o</em><em>r</em><em> </em><em>b</em><em>r</em><em>a</em><em>i</em><em>n</em><em>l</em><em>y</em><em> </em><em>u</em><em>s</em><em>e</em><em>r</em><em>:</em></h3>

<em>Just please, idols ,if we are going to answer questions here on brainly, don't do the ones from the internet, then just copy and paste </em>

<em>Just please, idols ,if we are going to answer questions here on brainly, don't do the ones from the internet, then just copy and paste You can search on the internet but make your own sentence okay? Thank you </em>

8 0
3 years ago
A sphere has a radius of 4 inches. What is the surface area of the smallest cube that could circumscribe the sphere?
vovikov84 [41]

Answer:

SA=384\ in^2

Step-by-step explanation:

we know that

The smallest cube that could circumscribe the sphere has a length side equal to the diameter of the sphere

In this problem

The radius of the sphere is r=4\ in

The diameter of the sphere is two times the radius

D=2r=2(4)=8\ in

so

The length side of the cube is

b=8\ in

Remember that

The surface area of a cube is equal to the area of its six faces

so

SA=6b^2

substitute the value of b

SA=6(8)^2

SA=384\ in^2

6 0
3 years ago
Based on the given information, what can you conclude, and why? (PLEASE HELP!)
pychu [463]
That would be the third option
6 0
3 years ago
Other questions:
  • Can somone pls help me? 3/5 of 65? And 2/3 of 210 and 2/7 of 42
    5·1 answer
  • The top of a desk would be a representation of
    9·1 answer
  • What is the the minimal education or degree i need to be a computer engineer?
    12·1 answer
  • What is 9 to the -2 power
    7·1 answer
  • Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 4x -
    11·1 answer
  • Match the result of solving an equation to the number of solutions the equation has
    11·1 answer
  • Mt. Everest, the highst elevation in asia, is 29,035 feet above sea level. The Dead Sea, the lowest elevation, is 1,349 feet bel
    15·1 answer
  • Fill the blank<br> A BLANK is an ordered set of numbers arranged according to a rule.
    12·2 answers
  • How to sketch this function y=x(squared) -2x+3
    14·1 answer
  • Joe's dad is ordering pizza for Joe and his friends. Joe says that he wants 5/8 of a
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!