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Svetradugi [14.3K]
3 years ago
7

The graph shows the dilation with respect to the origin of rhombus rhom

Mathematics
1 answer:
atroni [7]3 years ago
3 0
Do you have a picture?
You might be interested in
How do you find the derivative of 4
Nutka1998 [239]

by rule the derivative of a constant is 0

 so the answer for this is 0

5 0
3 years ago
The value of a $3000 computer decreases about 30% each year. write a function for the computers value V(t)
den301095 [7]

Answer:

Function for given situation is : V(t)=3000(0.70)^t

Value of computer after 4 years = $720.3.

Step-by-step explanation:

Given that the value of a $3000 computer decreases about 30% each year. Now we need to write a function for the computers value V(t). then we need to find about how much will the computer be worth in 4 years.

It clearly says that value decreases so that means function represents decay.

For decay we use formula:

A=P(1-r)^t

where P=initial value = $3000,

r= rate of decrease =30% = 0.30

t= number of years

A=V(t) = future value

so the required function is V(t)=3000(1-0.30)^t

or V(t)=3000(0.70)^t

Now plug t=4 years to get the value of computer after 4 years.

V(4)=3000(0.70)^4

V(4)=720.3

Hence final answer is $720.3.

7 0
3 years ago
Read 2 more answers
Can someone help me with this ASAP??
Lena [83]

Answer:

3/5

Step-by-step explanation:

because bc is 2/5 away from each other while bd is 5/5 away from each other. 5/5 - 2/5 = 3/5

8 0
3 years ago
Read 2 more answers
8x10^30/2x10^12 in scientific notation?
4vir4ik [10]

Answer:

4*10^18

Step-by-step explanation:

Easier to think of it as the factors out front (8 / 2) = 4

and subtract the exponents 30 - 12 = 18

= 4*10 ^18

5 0
4 years ago
Smplify the radical expression. How many different ways can you write your answer?
mel-nik [20]

Answer:

2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

Step-by-step explanation:

The given radical expression is

\sqrt[3]{16x^5y^3z}

We have to simplify the above expression.

The above expression can be written as

\sqrt[3]{(2\times 8)(x^{3+2})y^3z}

\sqrt[3]{(2\times 2^3)(x^3\times x^2)y^3z}    [\because a^{m+n}=a^ma^n]

\sqrt[3]{(2^3x^3y^3)(2x^2z)}

\sqrt[3]{(2xy)^3}\sqrt[3]{2x^2z}    [\because (ab)^m=a^mb^m]

2xy\sqrt[3]{2x^2z}    [\because \sqrt[n]{x^n}=x]

It can be written as exponent form.

2xy(2x^2z)^{\frac{1}{3}}    [\because \sqrt[n]{a}=a^{\frac{1}{n}}]

Therefore, the required expressions are 2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

5 0
3 years ago
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