Question

Please help!!!!

Answer 1

Answer:

Step-by-step explanation:

From the figure attached,

If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.

Therefore, sides sides CD and GH must be equal in measures.

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of the side CD having ends C(-4, 4) and D(0, 5) will be,

CD = $\sqrt{(-4-0)^2+(4-5)^2}$

CD = $\sqrt{(16+1)}$

     = $\sqrt{17}$

Length of GH having ends G(0, -4) and H(4, -5) will be,

GH = $\sqrt{(0-4)^2+(-4+5)^2}$

      = $\sqrt{16+1}$

      = $\sqrt{17}$

Therefore, m(CD) = m(GH)

Similarly, we can prove all corresponding sides of two figures equal in measure.

This shows ABCD ≅ EFGH.