Answer:
π×10^2=314.15
Step-by-step explanation:
hope it helps
Answer:
54 (also include units squared as the picture isn't clear)
Step-by-step explanation:
3×3=9 (area of square =l×b)
9×6= 54cm² (since a cube has 6 faces)
1/6* 1/6. Multiply the top number and the bottom numbers and you have 1/36.
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.
The question is not complete because it is not written correctly
Complete Question:
The drama club is holding auditions for five different parts in a one act play. If 9 people audition, how many ways can the roles be assigned?
a. 362,880
b. 15,120
c. 126
d. 120
Answer:
b. 15,120
Step-by-step explanation:
In other to solve the question above, we would use the formula for permutation.
This is because when assigning 5 DIFFERENT roles to 9 people, the order of assigning the roles is important. The formula for permutation, is used when order is involved.
Permutation (n, r) = nPr = n!/(n - r)!
In the above question,
n = 9 people
r = 5 different parts
9P5 = 9!/(9 - 5)!
= 9!/4! = 9×8×7×6×5×4×3×2×1/ 4×3×2×1
= 362880/ 24
= 15,120
Therefore, the number of ways that the roles can be assigned is 15,120 ways
