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3 years ago

3RD QUESTION. PLEASE HELP 20 POINTS!!!!!!!! ANSWER IN COMPLETE SENTENCES

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

7 0

Answer:

A: enlargement B: 2

Step-by-step explanation:

im pretty sure this is correct

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Linda enrolls for 10 credit-hours for each of two semesters at a cost of $500 per credit-hour (tuition and fees). In addition, t

kodGreya [7K]

I agree with the other answer

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3 years ago

What is the solution to this system of equations?

Maurinko [17]

Answer:

(x, y) = (5, -2)

Step-by-step explanation:

A graphing calculator provides a quick and easy way to find the solution.

_____

There are several other ways to solve these equations. Or you can estimate where the answer might be using logic like this:

The intercepts of the first equation are ...

x-intercept = 26/4 = 6 1/2
y-intercept = -26/3 = -8 2/3

So the graph of it will form a triangle with the axes in the 4th quadrant.

The intercepts of the second equation are ...

x-intercept = 11/3 = 3 2/3
y-intercept = 11/2 = 5 1/2

So the graph of it will form a triangle with the axes in the 1st quadrant. The x-intercept of this one is less than the x-intercept of the first equation, so the two lines must cross in the 4th quadrant.

The only 4th-quadrant answer choice is (5, -2).

3 0

3 years ago

What are the approximate solutions of 2x^2 + x = 14, rounded to the nearest hundredth?

Slav-nsk [51]

Hello,

2x²+x-14=0
Δ=1+4*14*2=113

x=(-1-√113)/4=-2,8839...≈-2.88
or x=(-1+√113)/4=2,40753≈2.41

7 0

3 years ago

A number decreased by the sum of the number and seven. what is the algebraic expression?

Aleks04 [339]

The answer would be x-(7+x)

5 0

2 years ago

Read 2 more answers

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago