Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

4 0

1 year ago

Necesito ayuda con el ejercicio de abajo, es de Física

Kryger [21]

No sé qué forma quieres que lo contestes pero es 278235/133 !

4 0

2 years ago

What is the area of the shaded region?<br> 3 cm

stiks02 [169]

Answer:

7.74cm ^2

Step-by-step explanation:

a=pie * r ^2

3.14*3^2=3.14*9=28.26 then you know all sides of a square are equal and 3 is half of 1 side so 6*6-=36 36-28.26=7.74

3 0

3 years ago