A car drvies at a speed of 60 mph for 30 minutes. Calculate how far it travles

A picture could hold to 12th of a gallon of water if Roger filled up nine pictures how much water would he have

TEA [102]

Answer:

He would have a very soggy picture!

OR if you mean the pitcher holds one twelvth of a gallon, he will have 9/12 or 3/4 of a gallon.

OR if you mean the pitcher holds two twelvths of a gallon, he ends up with 9 × 1/6 which is one and a half gallons.

Step-by-step explanation:

Spelling is important! A "picture" could be a drawing, a photograph, or a painting.

"Pitcher" could be a container for pouring liquids or a player who pitches the ball in a baseball game.

I know you wanted math help, but it is difficult to answer if I can't tell whether "to" meant "two" or he filled the pitcher to pour twelvths.

8 0

3 years ago

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi

Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$

n days:

This means that $s = \frac{\sigma}{\sqrt{n}}$

Applying the Central Limit Theorem to the z-score formula.

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

5 0

3 years ago

Ben can type 25 words in half a minute. At this rate, how many words can he type in 5 minutes?

mestny [16]

Answer:

The answer is C ФωФ

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A small business spend $23,000 for taxable items last year. The tax rate was 9.5%. How much did the small business pay in taxes

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