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2 years ago

PLEASE help me ASAP with this QUETION!!!!!!!!!!

Mathematics

1 answer:

Vlada [557]2 years ago

5 0

Answer:help with what

Step-by-step explanation:

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Find the volume of a cylinder with a height of 16ft and diameter of 7 feet. Write answer in pie

finlep [7]

Answer:

Step-by-step explanation:

volume of cylinder=V=πr^2h

given diameter=7 feet

radius=7/2 ft

height=16ft

v=π×7/2×7/2×16

=12.25×16×π

=196π

hope this helps

plzz mark me brainliest

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3 years ago

Please help me answer these thank you

ANEK [815]

It wouldn't play or else i would help

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2 years ago

NEED HELP ASAP (will mark brainliest)

klemol [59]

Answer: 30 feet away

7 0

2 years ago

Read 2 more answers

Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.

julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=4x^2+6y^2$

Let g(x,y)= $x^2+y^2=1$

We have to find the extreme values of the given function

$\nabla f(x,y)$

$\nabla g(x,y)=$

Using Lagrange multipliers

$\nabla f(x,y)=\lambda \nabla g(x,y)$

$f_x=\lambda g_x$

$8x=\lambda 2x$

Possible value x=0 or $\lambda=4$

If x=0 then substitute the value in g(x,y)

Then, we get $y=\pm 1$

$f_y=\lambda g_y$

$12y=\lambda 2y$

If $\lambda=4$ and substitute in the equation

Then , we get possible value of y=0

When y=0 substitute in g(x,y) then we get

$x=\pm 1$

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

$f(0,1)=6$

$f(0,-1)=6$

$f(1,0)=4$

$f(-1,0)=4$

Therefore, the maximum value of f on the circle $x^2+y^2=1$ is $f(0,\pm1)=6$ and minimum value of $f(\pm1,0)=4$

7 0

2 years ago

Having exactly the same shape and size

e-lub [12.9K]

Answer:

If two things have the same shape and size then they are <em>congruent</em> to one another. If they are only the same shape but not size, then they are similar.

4 0

1 year ago