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2 years ago

12

Hey guys please solve this basic equation for me 5 + 2x < 9

1 answer:

nikitadnepr [17]2 years ago

6 0

Answer:

x < 2

Step-by-step explanation:

Given

5 + 2x < 9 ( subtract 5 from both sides )

2x < 4 ( divide both sides by 2 )

x < 2

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aiden currently has a balance of $4443.48 in an account he has held for 17 years he open the account with initial deposit of $25

pickupchik [31]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4443.48\\
P=\textit{original amount deposited}\to& \$2567\\
r=rate\to r\%\to \frac{r}{100}\\
t=years\to &17
\end{cases}
\\\\\\
4443.48=2567(1+r17)\implies \cfrac{4443.48}{2567}=1+17r
\\\\\\
\cfrac{4443.48}{2567}-1=17r\implies \cfrac{\frac{4443.48}{2567}-1}{17}=r\implies 0.043\approx r
\\\\\\
0.043\approx\cfrac{r}{100}\implies 0.043\cdot 100\approx r\implies 4.3\%\approx r$

5 0

3 years ago

Please help!!! 10 points up!

Dimas [21]

Statements are all TRUE

sinA = $\frac{a}{c}$ and cosB = $\frac{a}{c}$

cscA = 1/sinA = 1/(a/c) = $\frac{c}{a}$ and secB = 1/cosB = 1/(a/c) = $\frac{c}{a}$

tanA = $\frac{a}{b}$ and cotB= 1/tanB = 1/ (b/a) = $\frac{a}{b}$

8 0

2 years ago

3×=21, the value of ×is

lord [1]

<em>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</em>

<em>➷ </em> $x + 3 = 21$ <em />

<em>➷ </em> $x = 21 - 3$ <em />

<em>➷ </em> $x = 18$ <em />

<em>✽</em>

<em>➶ Hope This Helps You!</em>

<em>➶ Good Luck (:</em>

<em>➶ Have A Great Day ^-^</em>

<em>↬ May ♡</em>

<em />

8 0

2 years ago

The ratio of 1/2 to 3 is equal to the ratio of 5 to what number<br><br><br><br>plz halp ;(

Dvinal [7]

Answer:

5 : 30

Step-by-step explanation:

Note that $\frac{1}{2}$ × 10 = 5

Thus 3 × 10 = 30

Hence

$\frac{1}{2}$ : 3 = 5 : 30

8 0

2 years ago

From a square piece of cardboard paper of area size 9 m2 , squares of the same size are cut off from each corner of the paper. T

levacccp [35]

Answer:

Max vol = 2 cubic metres

Step-by-step explanation:

Given that from a square piece of cardboard paper of area size 9 m2 , squares of the same size are cut off from each corner of the paper.

Side of the square = 3m

If squares are to be cut from the corners of the cardboard we have the dimensions of the box as

3-2x, 3-2x and x.

Hence x can never be greater than or equal to 1.5

V(x) = Volume = $V(x) = x(3-2x)^2\\= 9x+4x^3-12x^2$

We use derivative test to find the maxima

$V'(x) = 9+12x^2-24x\\V"(x) = 24x-24\\$

Equate I derivative to 0

$9+12x^2-24x=0\\x=1/2,3/2$

If x= 3/2 box will have 0 volume

So this is ignored

V"(1/2) <0

So maximum when x =1/2

Maximum volume

= $9(1/2)+4(1/2)^3-12(1/2)^2\\=2$ cubic metres

6 0

2 years ago