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Darina [25.2K]
2 years ago
9

The lengths of two sides of a triangle are 11 cm and 19 cm. Identify the range of possible lengths for the third side.

Mathematics
2 answers:
mamaluj [8]2 years ago
5 0

Answer:

2nd option

Step-by-step explanation:

Given 2 sides of a triangle then the third side x is in the range

difference of 2 sides < x < sum of 2 sides , that is

19 - 11 < x < 19 + 11

8 < x < 30

Veronika [31]2 years ago
5 0

Answer:

8 < x < 30

Step-by-step explanation:

The rule for side lengths of a triangle is:

the sum of two side's must be bigger than the third side and their difference must be smaller than the third side :

19 - 11 < x < 19 + 11

8 < x < 30

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Answer:

all the numbers are gong by adding 6

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3 years ago
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beth wants to make bags of party favors to give to her friends. Bracelets come in package of 10. Hair bows come in package of 4.
Paladinen [302]

10 = 2x5

4 = 2x2

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3 years ago
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
2 years ago
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melamori03 [73]

Answer:

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Step-by-step explanation:

Factor the equation to make the problem easier - you should have this:

(x - 18) (x + 18) = 1

Set each binomial to 1:

x - 18 = 1

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8 0
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Bezzdna [24]

Subtract the year the pilgrims sailed from the year you want to find the distance from:

2040 - 1620 = 420 years.

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