The social security deduction is given by 6.2% of the gross pay.
Thus, guven a gross pay of $37,890, the social security deduction is given by 0.062 x $37,890 = $2,349.18
Answer: lemme solve it ty
Step-by-step explanation:
hi
Answer:
Estimate is 150 and actual product is 138.
Step-by-step explanation:
To estimate products, we round the numbers to nearest unit place, 10th, 100th, 1000th, and so on.
Given are the numbers 3 and 46.
We can round 46 ≈ 50.
So Estimation would be 3 x 46 ≈ 3 x 50
3 times 5 is 15 and we can add zeros after it.
So estimation is 3 x 46 ≈ 150.
Now actual product would be...
3 times 6 is 18, so we note down 8 and 1 goes to carry over 4.
3 times 4 is 12 and carry 1 will be added in it, so 12 + 1 = 13.
It means the actual product is 3 x 48 = 138.
Answer:
We conclude that the function remains constant over the interval [0, 2].
Step-by-step explanation:
We know that if x increases from left to right and y remains constant, the function remains constant over a certain interval.
From the given graph below, it is clear that from x = 0 to x = 2 the value of y does not change.
In other words, the value of y remains constant from x = 0 to x = 2.
i.e.
at x = 0, y = 5
at x = 1, y = 5
at x = 2, y = 5
Therefore, we conclude that the function remains constant over the interval [0, 2].
Given the question: Arrange the reasons for the proof in the correct order.
Prove: If the diameter of a circle is 6 meters and the formula for
diameter is d = 2r, then the radius of the circle is 3 meters.
A. If r ≠ 3 m, then d ≠ 6 m. Since the contrapositive is true, the
original statement must also be true. Therefore, if the diameter of a
circle is 6 meters, then the radius is 3 meters.
B. Multiplication of real numbers shows that d = 2(2 m) = 4 m.
C. Substitute r = 2 m into d = 2r.
D. Assume that r ≠ 3 m. For example, the radius equals another length,
such as r = 2 m.
To prove that i<span>f the diameter of a circle is 6 meters and the formula for diameter is d = 2r, then the radius of the circle is 3 meters by contradiction, we assume that the radius in not equal to 3 meters, for </span>example, the radius equals another length,
such as r = 2 m.
Next, we substitute the value: r = 2m nto the original equation that says that d = 2r, i.e. d = 2(2m) = 4m which is not true and contradicts the original statement that the diameter of the circle is 6m.
Therefore, the arrangement of the proof is as follows:
D. Assume that r ≠ 3 m. For example, the radius equals another length,
such as r = 2 m.
C. Substitute r = 2 m into d = 2r.
B. Multiplication of real numbers shows that d = 2(2 m) = 4 m.
A. If r ≠ 3 m, then d ≠ 6 m. Since the contrapositive is true, the
original statement must also be true. Therefore, if the diameter of a
circle is 6 meters, then the radius is 3 meters.
D C B A.