3 years ago

What is the simplified form of the quantity of x plus 7, all over 2 − the quantity of x plus 4, all over 2?

Mathematics

1 answer:

astraxan [27]3 years ago

7 0

(x + 7)/2 - (x + 4)/2 = (x + 7 - (x + 4)/2 = (x + 7 - x - 4)/2 = 3/2

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20%20%3D%20%7B27%7D%5E%7B%3F%7D%20" id="TexFormula1" title=" \sqrt{3} = {27

marishachu [46]

Let the unknown be x

$\sqrt{3} = 27^x$

$3^\frac{1}{2} = 3^{3x}$

Both the base number are 3, so we equate the exponent:

$\dfrac{1}{2} = 3x$

$x = \dfrac{1}{2} \div 3$

$x = \dfrac{1}{2} \times \dfrac{1}{3}$

$x = \dfrac{1}{6}$

Answer: 1/6

3 0

3 years ago

If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain of (f circle g) (x)? (negative infinity, infinity) Left-bracket negative

n200080 [17]

Answer:

A. (-∞, ∞)

Step-by-step explanation:

f circle g (x) is another way of expressing f(g(x)). Basically, we have to plug g(x) into f(x) wherever we see x's.

f(x) = x^2 - 1

f(x) = (2x-3)^2 - 1

Now find the domain. I think the easiest way to do this is to graph it. I've attached the graph. You can also do it algebraically by thinking about it: it's a positive parabola (+x^2) and its minimum is -1, so its range will not be all real numbers, but its domain will certainly be. (The range would be answer choice B!)

Domain = (-∞, ∞)