Find the length of the pendulum if theperiod of its oscillation is two seconds
1 answer:
Answer:
L= 1m
Explanation:
<u>Data</u>
Period(T) = 2s
acc. due to gravity(g) = 9.8m/s
Length of pendulum (L) = ?
Relationship
T= (2π[L/g])^1/2
2= 2×3.14[ L/ 9.8 ] ^1/2
2 = 6.28[ L/9.8 ] ^ 1/2
square both sides to remove the square root ( i.e ^1/2 )
4 = 39.25[ L/ 9.8]
Divide both sides by 39.25
0.1091 = L/9.8
multiply both sides by 9.8
1.069 = L which is same as L = 1.069
Approximate to the nearest whole number
L = 1m
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