Answer:
They also gave suggestions on some modules and said they would like to work with his team in the future.
Explanation:
This statement suggests feedback because, here the client gives Richard and his team some suggestions on what they can do with the modules. It implies that the client must have tested the software application and observed its functionality.
Answer:
Challenge-Handshake Authentication Protocol (CHAP).
Explanation:
In Computer technology, authentication can be defined as the process of verifying the identity of an individual or electronic device. Authentication work based on the principle (framework) of matching an incoming request from a user or electronic device to a set of uniquely defined credentials.
Basically, authentication ensures a user is truly who he or she claims to be, as well as confirm that an electronic device is valid through the process of verification.
In this scenario, an organization wants to implement a remote dial-in server to ensure that personnel can connect to the organization's network from remote locations. The authentication protocol must include encryption to prevent hackers from accessing the network.
Hence, the protocol which should be used is Challenge-Handshake Authentication Protocol (CHAP).
A Challenge-Handshake Authentication Protocol (CHAP) can be defined as a standard network access control protocol in which a client program dials in to a network access server to receive a random value and identification number that can only be used once.
Answer:
Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.
;Include Irvine32.inc file used with link library for 32 bit applications
.386
.model flat,stdcall
.stack 4096
ExitProcess proto,dwExitCode:dword
INCLUDE Irvine32.inc
.data
myArray DWORD 0,2,5,9,10
arrSize = ($-myArray)/TYPE myArray
gapArr DWORD arrSize-1 DUP(?)
sum DWORD ?
.code
main PROC
;Call the procedure
call Clrscr
;Initialize ESI pointer
mov esi, 0
mov ecx, arrSize
dec ecx
L1:
mov eax, myArray[esi+4]
sub eax, myArray[esi]
mov gapArr[esi], eax
inc esi
loop L1
;Calculate the sum of gaps between array elements
mov sum, 0
mov esi, 0
mov ecx, arrSize
dec ecx
; move gapArr[esi] to a temporary register and then add that register value to sum
L2:
mov edx, gapArr[esi]
add sum, edx
inc esi
loop L2
INVOKE ExitProcess,0
main ENDP
END main
Explanation:
Answer:
$340
Explanation:
you have to multiply $400 bu 85% to get $340
<span>A. icons.
B. windows.
C. trackballs.
D. modems.</span>
Desktop publishing design tools are represented by <span>icons.
The answer is letter A. This is the easiest way to access the design tools when
in need.</span>
