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3 years ago

How do i convert y = 6x into y = mx + b form?

Mathematics

2 answers:

Margarita [4]3 years ago

7 0

Answer:

it already is in that form

y = 6x

technically Y = 6x + 0 could be the answer...

but in math we tend to not rite "obvious" information

to reduce clutter and confusion

+1 $x^{1}$ is technically correct but we drop the + sign for positive numbers

and also drop the exponent if it is a 1 ... similarly

+1 $x^{1}$ + 0 + 0 + 0 would also be silly and we don't write the zeros

+1 $x^{1}$ + 0 + 0 + 0 = x

Step-by-step explanation:

Setler [38]3 years ago

7 0

Answer:

Step-by-step explanation:

It's already in the form.

y = 6x

y = 6x + 0

m = 6

b = 0

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Given: △FKL, FK=a

LuckyWell [14K]

Answer:

$FL= \frac{a (\sqrt{3} + 1)}{\sqrt{2} }$

Step-by-step explanation:

As given in figure 1 below:

FK = a, m∠F = 45° and m∠L = 30°

Construction: Draw an altitude KE from point K on FL.

Now, In ΔFEK,

FE = EK (Sides opposite to equal angles of a triangle)

Let FE = EK = x

Now, using pythagoras In ΔFEK,

$(FK)^{2} = (FE)^{2} + (KE)^{2}$

$(a)^{2} = (x)^{2} + (x)^{2}$

$(a)^{2} = 2x^{2}$

$x = \sqrt \frac{a^{2} }{2} = \frac{a}{\sqrt{2} }$

∴ FE = EK = $\frac{a}{\sqrt{2} }$

Now in ΔEKL, EK = $\frac{a}{\sqrt{2} }$

Using trigonometry ratio,

TanФ = Altitude\ Base

$Tan \theta = \frac{KE}{EL}$

Tan 30° = $\frac{a/\sqrt{2} }{EL}$

$\frac{1}{\sqrt{3} } = \frac{a}{\sqrt{2} EL}$

$EL = \frac{\sqrt{3}a}{\sqrt{2} }$

Now FL = FE + EL

FE = $\frac{a}{\sqrt{2} }$ and $EL = \frac{\sqrt{3}a}{\sqrt{2} }$

∴ $FL = \frac{a}{\sqrt{2} } + \frac{\sqrt{3}a }{\sqrt{2} } = \frac{a (\sqrt{3} + 1)}{\sqrt{2} }$

4 0

4 years ago

I NEED HELP! Let me know how you got that answer I’m trying to understand and I’ll mark you brainliest :)

zlopas [31]

Answer:

A- (-1,0) B- (1,7) C- (6,5)

Step-by-step explanation:

these would be your new coordinates

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4 years ago

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Helpppppppp

wel

The hypotenuse can be solved by this formula. X^2 = 6^2 +6^2

X^2=64
Usually you cut it down to 8 but it wants the squared form so 64.

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3 years ago

Is the cordinates (2,4) (5,0) (6,8) (9,2) (11,6) functional?

Dmitrij [34]

Yes this is a function

The reason why is because the x coordinates do not repeat. Each x value maps to exactly one y value. For any input, there is exactly one output. If you were to graph all of these points, then the graph would pass the vertical line test.

If we had something like (2,4) and (2,0) then the input x = 2 would lead to multiple outputs (y = 4, y = 0) which would not make it a function; however we don't have any repeated x values here.

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Murrr4er [49]

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3 years ago

How do i convert y = 6x into y = mx + b form?​

How do i convert y = 6x into y = mx + b form?