All categories

3 years ago

SUPER URGENT!

Mathematics

1 answer:

Lady_Fox [76]3 years ago

5 0

1) 2x+(-2x+2x)=2x
2) 4x+5+(-3x^2-3x)=-3x^2+x+5

You might be interested in

Ricky earned $102 in 8 hours

Mariulka [41]

102/8 = 12.75

Your answer would be $12.75

Hope this helps!

4 0

3 years ago

Please what’s the answer

kozerog [31]

Answer:

It's the second one.

7 0

3 years ago

When a plane intersects a sphere, what two-dimensional shape describes the cross-section?

trasher [3.6K]

Answer:

A Circle

Step-by-step explanation:

4 0

2 years ago

HELP DUE IN 15 MINS!

boyakko [2]

Answer:

r = $2\sqrt{5}$

$(x - 3)^{2} + ( y - 2)^{2} = 20$

Is this a live test question or a homework question?

Step-by-step explanation:

the radius is the distance between (3, 2) and (5, -2)

$r^{2}$ = ${(3 - 5)^{2} + (2 + 2)^{2} }$

= $(-2)^{2} + 4^{2}$

= 4 + 16 = 20

r = $\sqrt{20 } = 2\sqrt{5}$

Equation of circle: $(x - 3)^{2} + ( y - 2)^{2} = 20$

8 0

3 years ago

Read 2 more answers

Given the isosceles trapezoid below, find AG.<br> Show all the work

Dmitry [639]

We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

$40 - 24 = 16$

Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of $GT$ and $EF$

$\frac{16}{2} = 8$

Finally, we can use the Pythagorean Theorem to find the length of $AG$ :

$AG^{2} + GT^{2} = AT^{2}$

$AG^{2} + 8^{2} = 10^{2}$

$AG^{2} + 64 = 100$

$AG^{2} = 36$

$AG = 6$

8 0

2 years ago