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mojhsa [17]
3 years ago
9

Erica babysits for 4 ½ hours and is paid $27. If the people she babysits for have $57 to pay her, how long can they stay out?

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

5 Hours left

Step-by-step explanation:

27/4.5=6

57/6=9.5

9.5-4.5=5

5 Hours Left :)

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Answer:

79

Step-by-step explanation:

Since the triangles are similar, the sides that are the same length have angles that are the same size at the top.

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Can someone help me with this
leonid [27]

Answer:

(y-b) /x = m

Step-by-step explanation:

y = mx+b

Subtract b from each side

y -b = mx+b-b

y-b = mx

Divide each side by x

(y-b) /x = mx/x

(y-b) /x = m

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3 years ago
A pole that is 3.5 m tall casts a shadow that is 1.38 m long. At the same time, a nearby tower casts a shadow that is 49.75 m lo
Yuri [45]

Answer: 126

Step-by-step explanation: i am so sorry if i am wrong

3 0
3 years ago
Please help me! I am really struggling with this...
Alexeev081 [22]

Answer:

44°

Step-by-step explanation:

The secant- secant angle y is half the difference of the measure of its intercepted arcs, that is

\frac{1}{2}(BHF - CGJ ) = y , that is

\frac{1}{2}(156 - CGH) = 56° ( multiply both sides by 2 )

156 - CGH = 112° , thus

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4 0
4 years ago
I need help with this. Thanks <br><br><br> I need to find the degree
scoundrel [369]

Answer:

  119.05°

Step-by-step explanation:

In general, the angle is given by ...

  θ = arctan(y/x)

Here, that becomes ...

  θ = arctan(9/-5) ≈ 119.05°

_____

<em>Comment on using a calculator</em>

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

__

It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

  Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

  θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

3 0
4 years ago
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