The total number of pencils is 2,160. When estimating to the nearest hundredth one gets 2,200, which is an underestimate.
The advantage of underestimating is that your answer is more accurate than an overestimate.
Volume of box = length x width x height = 19 x (1.7 x 12) x 6 = 19 x 20.4 x 6 = 2,325.6 cubic inches.
Answer:
There are no real solutions for the given question (6c - 5) + (-6c)
Step-by-step explanation:
Solution for (6c-5) + (-6c)
Simplifying
,
(6c + -5) + (-6c) = 0
Reordering the given terms:
(-5 + 6c) + (-6c) = 0
Remove "parenthesis" around (-5 + 6c)
-5 + 6c + (-6c) = 0
Combining like terms it becomes 6c + (-6c) = 0
-5 + 0 = 0
-5 = 0
Solving
-5 = 0
we could not find the solution for the given (6c - 5) + (-6c).
The given equation is not a valid one, the "left hand side" and "right hand side" are unequal, and therefore there is no solution.
Answer:
208.837209
Step-by-step explanation:
Data provided in the question:
The output of 35920 / 172 on calculator = 208.837209
Now,
All the digits or figures that are non-zero are considered as significant figures.
also, the number zero between any two consecutive number is considered as significant figure.
Thus,
for the given output the all the non-zero digits are significant, also the zeros are between the two consecutive number
Hence, the correct answer is 208.837209
Answer:
Option B. 8 mi, 9 mi, 2 mi
Step-by-step explanation:
The option A doesn't have a set of numbers which could be the lengths of the sides of a triangle. The numbers 1,9,10 mean that the longest side is exactly the sum of the others. The only possible way is they lie in the same line, no triangle is formed
Option C gives the numbers 1,9,11. It's impossible to have a side of 11 when you have the sum of the others less than 11. The maximum extension of the other sides (forming a line) won't be enough to reach the length of 11
Option D is also infeasible for the same reason as the option A. The three lines must be aligned to be connected in its extremes
Option B is the only one who can provide a set of possible lengths of a triangle since the sum of the shortest sides is greater than the third. If we open wide enough the angle between the 2 mi side and the 8 mi side, we would eventually connect the 9 mi side and form a triangle
