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2 years ago

3x - 2y + 8 (5y - 1 + 3x) Add the polynomials

Mathematics

1 answer:

ololo11 [35]2 years ago

7 0

Answer:

hope it helps I have made it in pic

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Refer to the triangle below. If a = 4 and b = 6, solve for c. show work Also, give the unsimplified radical form answer and then

9966 [12]

Look at the image below where I labeled the sides

To solve this you must use Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 4

b = 6

c = unknown

^^^Plug these numbers into the theorem

$4^{2} +6^{2} =c^{2}$

simplify

16 + 36 = $x^{2}$

52 = $x^{2}$

To remove the square from x take the square root of both sides to get you...

√52 = x

^^^Unsimplified radical

2√13

^^^Simplified radical

7.21

^^^Rounded to hundedths

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0

3 years ago

Find the circumference for 6 and 8

Naya [18.7K]

Answer:
6. 98.01
8. 32.04

5 0

3 years ago

The left side of a solid block is held at a constant temperature of 200°C. The temperature profile within the block is given by

Nikitich [7]

Answer:

with T = 50⁰C, we have:

50 = 200 - 5x - x²

<=> x² + 5x = 150

<=> x² + 5x - 150 = 0

=> x = 10

6 0

2 years ago

Does -2(z+3)-z=-z-4(z+2) have one,zero or infinite solutions

Andrew [12]

Hello from MrBillDoesMath!

Answer:

One solution (z = -1)

Discussion:

-2(z+3)-z=-z-4(z+2) =>

-2z -6 -z = -z -4z - 8 =>

-3z -6 = -5z -8 => add 6 to both sides

-2z = -5z -2 => add 5z to both sides

3z = -5z +5z -3 =>

3z = -3 =>

z = -1

Thank you,

MrB

6 0

3 years ago

Question number 8. Prove that 3 + √5 is an irrational number.

Marina86 [1]

Answer :

Let's assume the opposite of the statement i.e., 3 + √5 is a rational number.

$\\ \sf \: 3 + \sqrt{5} = \frac{a}{b} \\ \\ \qquad \: \tiny \sf{(where \: \: a \: \: and \: \: b \: \: are \: \: integers \: \: and \: \: b \: \neq \: 0)} \\$

$\\ \sf \: \sqrt{5} = \frac{a}{b} - 3 = \frac{a - 3b}{b} \\$

Since, a, b and 3 are integers. So,

$\\ \sf \: \frac{p - 3b}{b} \\ \\ \qquad \tiny \sf{ \: (is \: \: a \: \: rational \: \: number \:) } \\$

Here, it contradicts that √5 is an irrational number.

because of the wrong assumption that 3 + √5 is a rational number.

$\\$

Hence, 3 + √5 is an irrational number.

7 0

3 years ago