Ok so there are no real solutions for xy=15000 and x+y=5
there are immaginary solutions though so
xy=15000
x+y=5
x+y=5
y=5-x
x(5-x)=15000
-x^2+5x=15000
0=x^2-5x+15000
quadriacic formula
if ax^2+bx+c=0, then
x=

x^2-5x+15000
a=1
b=-5
c=15000
x=

x=

x=

x=

so the numbers are

and
The third option is the answer
Answer: (5^3) / (5^7) = 5^ -4
or
1 / 5^4
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
We simply start by opening up the bracket
we have this as:
x^2(x-3x) = x^3 - 3x^2
The degree is simply the highest power of x
This is 3