If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
G >\ -4 ( g is greater than or equal to negative 4 )
Answer:
The value of 
is 16.
Step-by-step explanation:
The given expression is 
.
Put x = 2 in the above expression as follows :
Hence, the final answer is 16.
LCM:
10: 0,10,20,30,40,50
4: 0,4,8,12,16,20
ANSWER IS 20
LCM:
10: see above numbers
6: 0,6,12,18,24,30
ANSWER IS 30
So, 10 and 8 would be 40
Answer:
24 green marbles
Step-by-step explanation:
ez maths
