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11Alexandr11 [23.1K]
3 years ago
5

HELLPPPP PLEASEEE!!

Mathematics
2 answers:
Arada [10]3 years ago
7 0

Answer:

$0.05

Step-by-step explanation:

<3

ladessa [460]3 years ago
3 0
Chewing is freee wdymmm???
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What must be added to f(x) = 4x4 + 2x3 -2x2 +x - 1, so that the resulting  polynomial  is divisible  by  g(x) = x2 +2x -3?​
s344n2d4d5 [400]

Answer:

p(x) = -4*x^4  - 2*x^3 + 3*x^2 + 1*x - 2

Step-by-step explanation:

We want to find a polynomial p(x), such that if we add that polynomial to:

f(x) = 4*x^4 + 2*x^3 - 2*x^2 + x - 1

we get:

g(x) = x^2 + 2*x - 3

This is:

f(x) + p(x) = g(x)

Notice that f(x) is a polynomial of degree 4 and g(x) is a polinomial of degree 2, so p(x) must be also a polynomial of degree 4.

p(x) = a*x^4 + b*x^3 + c*x^2 + d*x + e

Then we get:

(4*x^4 + 2*x^3 - 2*x^2 + x - 1) + (a*x^4 + b*x^3 + c*x^2 + d*x + e) = x^2 + 2*x - 3

We can simplify the left side to:

(4 + a)*x^4 + (2 + b)*x^3 + (-2 + c)*x^2 + (1 + d)*x + (-1 + e) =  x^2 + 2*x - 3

Because in the right side we do not have terms with exponent 4 and 3, we must have that:

4 + a = 0

2 + b = 0

and for the other exponents of x we just match the exponent in the left side with the correspondent one in the right side:

(-2 + c) = 1

(1 + d) = 2

(-1 + e) = -3

Solving the 5 equations we get:

a = -4

b = -2

c = 1 + 2 = 3

d = 2 - 1 = 1

e = -3 + 1 = -2

Then the equation for p(x) is:

p(x) = -4*x^4  - 2*x^3 + 3*x^2 + 1*x - 2

6 0
3 years ago
The applicants for a soccer coaching position were asked how many years of
Naily [24]

On this problem you have to make sure the dot plot and the dots on it match the ones for the problem. It should only have one dot for 1, 4 for 2's, 2 for 4's...etc.

8 0
4 years ago
Julie has a jelwery box shaped like a cube.The volume of the jelwelry box is v cubic inches.Write an expression that represents
Usimov [2.4K]

Answer:

Edge length in inches = 3√(v in³)

Step-by-step explanation:

A jewelry box is shaped like a cube, with it's volume as v cubic inches.

The formula for the volume of a cube = (edge length)³

From the question, we are asked to write an expression that represents the edge length of julies jelwery box in inches

volume of a cube = (edge length)³

v in³ = edge length ³

We cube root both side

= 3√(v in³) = 3√(edge length³)

Edge length = 3√(v in³)

Therefore, the expression that represents the edge length of julies jelwery box in inches is:

Edge length in inches = 3√(v in³)

4 0
3 years ago
15.
boyakko [2]

Explanation:

a)

{3 \choose 2} = \frac{3!}{2!(3-2)!} = \frac{6}{2*1} = 3

{3 \choose 1} = \frac{3!}{1!(3-1)!} = \frac{6}{1*2} = 3

b) First, we have that

{n \choose k} = \frac{n!}{k!(n-k)!}

On the other hand,

{n \choose n-k} = \frac{n!}{(n-k)!(n(n-k))!} = \frac{n!}{(n-k)!k!}

Therefore, both expressions are equal. This makes sense, because selecting k elements from a group of n is the same than specify which elements you will not select. In order to specify those elements you need to select the n-k elements that will not be selected. Hence, each time you are selecting k from n, you are also selecting n-k from n, and from that reason both combinatorial numbers are equal.

4 0
3 years ago
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Thomas lives more than 0.55 km and less than 0.75 km from his school.
S_A_V [24]

Answer:

C 0.60km

I hope this answer helps if you have any questions just ask

6 0
3 years ago
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