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Bogdan [553]
3 years ago
7

State whether the following statements are true or false, and explain your reasoning.

Mathematics
2 answers:
aivan3 [116]3 years ago
8 0

Answer:

Step-by-step explanation:

shbhebvhbhv

Masja [62]3 years ago
6 0

Answer:

Step-by-step explanation:

a) A square is a rectangle.   True

Reason: Property of Rectangle: (i) Opposite sides are equal and parallel. (ii) Each angle is 90 (iii) Diagonals are equal and bisect each other.

A square hold all these properties. A square is  a rectangle.

b) A polygon with 21 sides has 432 possible diagonals. False

Reason: Number of diagonals of a polygon = \frac{n(n-3)}{2}

n --> number of sides of a polygon.

= \frac{21*18}{2} = 189 diagonals

c) All three angles in an Isosceles triangle are equal. False

Reason: In an isosceles triangle, two angles are equal.

If three angles are equal, then that is an equilateral triangle.

d) The measures of the exterior angles of a nonagon, a nine-sided figure, have a sum of 360°. True.

Reason: The sum of measures of the exterior angles  of any polygon is 360

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The perimeter of XYZ is ___ units.
In-s [12.5K]

Look at the picture.

ZY = 5+3=8

For XY and ZX use the Pythagorean theorem.

XY^2=3^2+4^2\\\\XY^2=9+16\\\\XY^2=25\to XY=\sqrt{25}\\\\XY=5

ZX^2=5^2+4^2\\\\ZX^2=25+16\\\\ZX^2=41\to ZX=\sqrt{41}

The perimetero fo XYZ:

P_{\triangle XYZ}=8+5+\sqrt{41}=\boxed{13+\sqrt{41}}

7 0
3 years ago
Age Problem. Please help. I suck at these.
eimsori [14]
Let Cynthia's age be C, then Abigail's age A

since Abigail is 8 years older, her age A = C+8.

20 years ago Cynthia's she was C-20 and Abigail was A-20=3(C-20)

A-20=3C-60
A=3C-40
but we just said A=C+8
so 3C-40=C+8
2C=48
C=24
A=24+8=32

Cynthia's age is 24 and Abigail's age is 32
7 0
3 years ago
Keke has 12 cups and 17 plates for a party how many cups does keke have
vodka [1.7K]

Im pretty sure that she has 12 cups.

4 0
3 years ago
Read 2 more answers
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
A cat us running away from a dog .after 5 seconds it is 16 feet away from the dog and after 11 seconds it is 28 feet away from t
kvasek [131]
11< or equal to x i think

8 0
3 years ago
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