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fomenos
3 years ago
10

Samson owes his friend

Mathematics
2 answers:
WINSTONCH [101]3 years ago
6 0
The answer would be $124.50:)
Anuta_ua [19.1K]3 years ago
6 0
Ok .……………………124.50 ok
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Find the slope of the line that passes through the points (10,8) and (4,12)​
JulsSmile [24]

Answer:

The slope is -2/3

Step-by-step explanation:

To find the slope of a line between two points, we use the equation

m = (y2-y1)/ (x2-x1)

where (x1,y1) and (x2,y2) are the two points

m = (12-8)/(4-10)

   = 4/-6

   = -2/3

The slope is -2/3

6 0
3 years ago
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1.75 + .75m = 4.75 what’s the answer in solution for this problem
ELEN [110]

Answer:

m=4

Step-by-step explanation:

We are to find the value of m in the question

1.75+0.75m=4.75

Let's start by substrating 1.75 from both sides

0.75m=3

We will have to make m the subject of formula by dividing both sides by 0.75

m=4

Therefore the final answer for m is 4

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3 years ago
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Mass of the prism ?
Anna35 [415]

Answer:

I think the answer is density

Step-by-step explanation:


5 0
4 years ago
A gardener is planting two types of trees: Type A is 8 feet tall and grows at a rate of 3 inches per year. Type B is 7 feet tall
777dan777 [17]

Answer:

Exactly 12 years it will take for these trees to be the same height

Step-by-step explanation:

Slope intercept form: An equation of line is in the form of y = mx+b where m is the slope or unit rate and b is the y-intercepts.

Let x represents the time in years and y represents the height of the tree.

Use conversion:

1 ft = 12 inches

As per the given statement:

Type A is 8 feet tall and grows at a rate of 3 inches per year.

⇒unit rate per year = 3 inches = \frac{1}{4} ft

Then, we have;

y =\frac{1}{4}x + 8                      ......[1]

Similarly for;

Type B  is 7 feet tall and grows at a rate of 4 inches per year.

⇒unit rate per year = 4 inches = \frac{1}{3} ft

then;

y =\frac{1}{3}x + 7                   .....[2]

To find after how many years it will take for these trees to be the same height.

Since, trees to be the same height;

⇒equate [1] and [2], to solve for x;

\frac{1}{4}x + 8 = \frac{1}{3}x +7

Subtract 7 from both sides we get;

\frac{1}{4}x + 8-7= \frac{1}{3}x +7-7

Simplify:

\frac{1}{4}x + 1= \frac{1}{3}x

Subtract \frac{1}{4}x from both sides we get;

1= \frac{1}{3}x-\frac{1}{4}x

Simplify:

1 = \frac{x}{12}

Multiply both sides by 12 we get;

x = 12

Therefore, exactly it will take for these trees to be the same height is, 12 years

8 0
3 years ago
Prove cosh 3x = 4 cosh^3 x - 3 cosh x.
Snezhnost [94]
Prove we are to prove  4(coshx)^3 - 3(coshx) we are asked to prove 4(coshx)^3 - 3(coshx) to be equal to cosh 3x
= 4(e^x+e^(-x))^3/8 - 3(e^x+e^(-x))/2 = e^3x /2 +3e^x /2 + 3e^(-x) /2 + e^(-3x) /2 - 3(e^x+e^(-x))/2 = e^(3x) /2 + e^(-3x) /2 = cosh(3x) = LHS Since y = cosh x satisfies the equation if we replace the "2" with cosh3x, we require cosh 3x = 2 for the solution to work. 
i.e. e^(3x)/2 + e^(-3x)/2 = 2 
Setting e^(3x) = u, we have u^2 + 1 - 4u = 0 
u = (4 + sqrt(12)) / 2 = 2 + sqrt(3), so x = ln((2+sqrt(3))/2) /3, Or u = (4 - sqrt(12)) / 2 = 2 - sqrt(3), so x = ln((2-sqrt(3))/2) /3, 
Therefore, y = cosh x = e^(ln((2+sqrt(3))/2) /3) /2 + e^(-ln((2+sqrt(3))/2) /3) /2 = (2+sqrt(3))^(1/3) / 2 + (-2-sqrt(3))^(1/3) to be equ
= 4(e^x+e^(-x))^3/8 - 3(e^x+e^(-x))/2 
= e^3x /2 +3e^x /2 + 3e^(-x) /2 + e^(-3x) /2 - 3(e^x+e^(-x))/2 
= e^(3x) /2 + e^(-3x) /2 
= cosh(3x) 
= LHS 

<span>Therefore, because y = cosh x satisfies the equation IF we replace the "2" with cosh3x, we require cosh 3x = 2 for the solution to work. </span>

i.e. e^(3x)/2 + e^(-3x)/2 = 2 

Setting e^(3x) = u, we have u^2 + 1 - 4u = 0 

u = (4 + sqrt(12)) / 2 = 2 + sqrt(3), so x = ln((2+sqrt(3))/2) /3, 
Or u = (4 - sqrt(12)) / 2 = 2 - sqrt(3), so x = ln((2-sqrt(3))/2) /3, 

Therefore, y = cosh x = e^(ln((2+sqrt(3))/2) /3) /2 + e^(-ln((2+sqrt(3))/2) /3) /2 
= (2+sqrt(3))^(1/3) / 2 + (-2-sqrt(3))^(1/3)
3 0
4 years ago
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