Evaluating Equations f(5)=4x^2-x+9

Mathematics

1 answer:

zavuch27 [327]3 years ago

7 0

Answer:

404

Step-by-step explanation:

20^2-5+9=

400+4= 404

You might be interested in

A circle has a diameter with endpoints at 3 – 5i and –8 + 2i. What is the center of the circle?

bagirrra123 [75]

So we got the real axis and the imaginary axis
we just need to find the average of the 2 points

remember
midpoint of (x1,y1) and (x2,y2) is

((x1+x2)/2,(y1+y2)/2)
so

average of 3 and -8 is -5/2
average of -5i and 2i is -3/2i

center is -5/2-3/2i

3 0

4 years ago

Read 2 more answers

Write the general equation for the circle that passes through the points (1, 1), (1, 3), and (9, 2).

Burka [1]

Step-by-step explanation:

As we know that

The circle center is equidistant from all three points, the distance being the circle radius.

Any point equidistant from two points must lie on the perpendicular bisector of the line segment which join those two points.

Which is, on the line through the midpoint of the line segment, perpendicular to the line segment.

The perpendicular bisector of the line segment joining the points (1, 1) and (1, 3) will be:

$\:y=\:\frac{1+3}{2}=\frac{4}{2}=2$

The perpendicular bisector of the line segment joining the points (1, 3), and (9, 2) will be:

$x=\:\frac{1+9}{2}=\frac{10}{2}=5$

These intersect at the center of the circle (5, 2).

The distance between (1, 1) and (5, 2) will be:

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$