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3 years ago

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Which of the following is not a typical characteristic of a linear programming problem?

1 answer:

adell [148]3 years ago

6 0

The answer is c. The problem can be solved graphically

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bs-1%7D%7B4%7D%3D%20%5Cfrac%7B4%7D%7B8%7D%20%20%3Cbr%3E%0Asolve%20for%20s" id="Tex

alex41 [277]

Simplify <span /><span><span><span><span><span><span><span><span><span>4</span><span /></span><span><span>8</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>48</span></span> to <span /><span><span><span><span><span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>12</span></span>
<span /><span><span><span><span><span><span><span><span><span><span>s</span><span>−</span><span>1</span></span><span /></span><span><span>4</span><span /></span><span><span /><span /></span></span></span><span>=</span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>s−14=12</span></span>
2<span> </span>Multiply both sides by <span /><span><span><span><span><span><span>4</span></span><span /></span></span><span /></span><span>4</span></span>
<span /><span><span><span><span><span><span>s</span><span>−</span><span>1</span><span>=</span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span><span>×</span><span>4</span></span><span /></span></span><span /></span><span>s−1=12×4</span></span>
<span> </span>Simplify <span /><span><span><span><span><span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span><span>×</span><span>4</span></span><span /></span></span><span /></span><span>12×4</span></span> to <span /><span><span><span><span><span><span><span><span><span>4</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>42</span></span>
<span /><span><span><span><span><span><span>s</span><span>−</span><span>1</span><span>=</span><span><span><span><span>4</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>s−1=42</span></span>
Simplify <span /><span><span><span><span><span><span><span><span><span>4</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>42</span></span> to <span /><span><span><span><span><span><span>2</span></span><span /></span></span><span /></span><span>2</span></span>
<span /><span><span><span><span><span><span>s</span><span>−</span><span>1</span><span>=</span><span>2</span></span><span /></span></span><span /></span><span>s−1=2</span></span>
Add <span /><span><span><span><span><span><span>1</span></span><span /></span></span><span /></span><span>1</span></span> to both sides
<span /><span><span><span><span><span><span>s</span><span>=</span><span>2</span><span>+</span><span>1</span></span><span /></span></span><span /></span><span>s=2+1</span></span>
Simplify <span /><span><span><span><span><span><span>2</span><span>+</span><span>1</span></span><span /></span></span><span /></span><span>2+1</span></span> to <span /><span><span><span><span><span><span>3</span></span><span /></span></span><span /></span><span>3</span></span>
<span /><span><span><span><span><span><span>s</span><span>=</span><span>3</span></span><span /></span></span><span /></span><span>s=3
</span></span>

7 0

3 years ago

Read 2 more answers

Experimentally verify sum of three angles of an triangle is 180⁰.

svetlana [45]

Draw line a through points A and B. Draw line b through point C and parallel to line a.

Since lines a and b are parallel, <)BAC = <)B'CA and <)ABC = <)BCA'.

It is obvious that <)B'CA + <)ACB + <)BCA' = 180 degrees.

Thus <)ABC + <)BCA + <)CAB = 180 degrees.

Lemma

If ABCD is a quadrilateral and <)CAB = <)DCA then AB and DC are parallel.

Proof

Assume to the contrary that AB and DC are not parallel.

Draw a line trough A and B and draw a line trough D and C.

These lines are not parallel so they cross at one point. Call this point E.

Notice that <)AEC is greater than 0.

Since <)CAB = <)DCA, <)CAE + <)ACE = 180 degrees.

Hence <)AEC + <)CAE + <)ACE is greater than 180 degrees.

Contradiction. This completes the proof.

Definition

Two Triangles ABC and A'B'C' are congruent if and only if

|AB| = |A'B'|, |AC| = |A'C'|, |BC| = |B'C'| and,

<)ABC = <)A'B'C', <)BCA = <)B'C'A', <)CAB = <)C'A'B'.

4 0

3 years ago

Hello i need help with this question

scoundrel [369]

Answer:

4pf

Step-by-step explanation:

4 0

3 years ago

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Help please <3 <3 <3

fomenos

Answer:

A group of ten people would be willing to spend 135$

tell me if im wrong plz

Step-by-step explanation:

4 0

3 years ago

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Describe the image of a dilation with a scale factor of 1

Whitepunk [10]

<span>With a scale factor of 1, the image is exactly the same size as the original object.</span>

3 0

3 years ago