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alexandr1967 [171]

4 years ago

13

Larinda cooked a 4-kilogram roast.The roast left over after the meal weighed 3 kilograms. How many grams of roast were eaten dur

ing that meal?

1 answer:

Oxana [17]4 years ago

8 0

4 (originally) - 3 (leftover) = 1 KG (eaten)

1* ( 1000) = 1000g

(there is 1000g in 1 KG)

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Find the outlier of the data set. <br> 43, 69, 49, 78, 88, 54, 73, 194, 54, 59, 70

jenyasd209 [6]

Answer:

194

Step-by-step explanation:

because no one else is above 100

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3 years ago

Solve. 5=15x−3 Enter your answer in the box. x =

guajiro [1.7K]

Here I'll help you:
In order to solve the problem we must take the "x" to one side, and the numbers to the other side. When we move the three to the other side of the equation, we must change the "negative" to a positive [if it were to be positive, we'd make it negative.]

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4 0

3 years ago

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33) What value for x makes this equation true? 4x + 3 = 23

Tju [1.3M]

Answer:

x = 5

Step-by-step explanation:

4x + 3 = 23

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3 0

3 years ago

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Find a linear function h, given h(3)=-10 and h(-4)=25 . Then find h(2).

madam [21]

Find a linear function h, given h( 3)=-10 and h(-4 )=25 . Then find h(2 ).

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3 years ago

Calculating conditional probability

laila [671]

Complete Question

Calculating conditional probability

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom.

Here are the results:

Bride :29

Groom :30

BOTH : 20

Given that a randomly selected guest is a friend of the groom, find the probability they are a friend of the bride.

P (bride | groom)

Answer:

The probability is $P(B|G) = \frac{2}{3}$

Step-by-step explanation:

The sample size is $n = 80$

The friend of the groom are $G = 30$

The friend of the groom are $B = 29$

The friend of both bride and groom are $Z = 20$

The probability that a guest is a friend of the bride is mathematically represented as

$P(B) = \frac{29}{80}$

The probability that a guest is a friend of the groom is mathematically represented as

$P(G) = \frac{30}{80}$

The probability that a guest is both a friend of the bride and a friend of the groom is mathematically represented as

$P(B \ n \ G) = \frac{20}{80}$

Now

$P(B|G)$ is mathematically represented as

$P(B|G) = \frac{P(B \ n \ G)}{P(G)}$

Substituting values

$P(B|G) = \frac{\frac{20}{80} }{\frac{30}{80} }$

$P(B|G) = \frac{2}{3}$

6 0

3 years ago