x-intercept = (15, 0) y-intercept = (0, 3)
slope (m) = (y₂ - y₁)/(x₂ - x₁) = (0 - 3)/(15 - 0) = -3/15 = -1/5
Point-Slope formula: y - y₁ = m(x - x₁) ; where (x₁, y₁) is one of the given points
y - 0 = (-1/5)(x - 15)
-5y = x - 15
x + 5y = 15
Answer: x + 5y = 15
Answer:
A.
Statement: ∠6 ≅ ∠14
Reason: For parallel lines cut by a transversal, corresponding angles are congruent.
Step-by-step explanation:
In the figure attached, a plot of the problem is shown.
Given p || q and r is a transversal which cut p and q, then ∠1 ≅ ∠5 and ∠2 ≅ ∠6.
Given r || s and q is a transversal which cut r and s, then ∠6 ≅ ∠14 and ∠8 ≅ ∠16.
From the picture we see that ∠1 and ∠2 are supplementary, that is, their addition is equal to 180º. ∠2 ≅ ∠6 and ∠6 ≅ ∠14, then ∠2 ≅ ∠14, in consequence ∠1 and ∠14 are supplementary.
Answer: (4,-3)
Step-by-step explanation: