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LenaWriter [7]
3 years ago
8

Help

Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

ANSWER: 8TT units

Step-by-step explanation:

hope it helps thanks❤

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Solve for x and then determine the measure of the exterior angle.
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Answer:

x=25, 120

Step-by-step explanation:

The two angles form a straight line so they add to 180

60 + 4x +20 =180

Combine like terms

4x+80 = 180

Subtract 80 from each side

4x+80-80 =180-80

4x= 100

Divide by 4

4x/4 =100/4

x= 25

The exterior angle is

4x+20 = 4*25+20 =100+20 =120

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for x = 2

Step-by-step explanation:

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An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the
sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that \mu = 72.3, \sigma = 8

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

Z = \frac{X - \mu}{\sigma}

1.34 = \frac{X - 72.3}{8}

X - 72.3 = 1.34*8

X = 83

The minimum score required for an A grade is 83.

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